Problem 8

Simplify the given code using your knowledge of map, slices, and pointers. Don't remove load, update it. The output should be the same

simplify([]string{"a", "b", "c"}) // map[a:0 b:1 c:2]

simplify([]string{"z", "y", "x", "u", "v"}) // map[u:3 v:4 x:2 y:1 z:0]