package
0.0.0-20241101153438-fc0a12dbc586
Repository: https://github.com/guvanchhojamov/code-ship.git
Documentation: pkg.go.dev
# README
151. Reverse Words in a String
Problem Statement
Given an input string s
, reverse the order of the words.
A word is defined as a sequence of non-space characters. The words in s
will be separated by at least one space.
Return a string of the words in reverse order concatenated by a single space.
Note that s
may contain leading or trailing spaces or multiple spaces between two words. The returned string should only have a single space separating the words. Do not include any extra spaces.
Examples
Example 1:
- Input:
s = "the sky is blue"
- Output:
"blue is sky the"
Example 2:
- Input:
s = " hello world "
- Output:
"world hello"
- Explanation: Your reversed string should not contain leading or trailing spaces.
Example 3:
- Input:
s = "a good example"
- Output:
"example good a"
- Explanation: You need to reduce multiple spaces between two words to a single space in the reversed string.
Constraints
- ( 1 \leq s.length \leq 10^4 )
s
contains English letters (upper-case and lower-case), digits, and spaces' '
.- There is at least one word in
s
.
Follow-up
If the string data type is mutable in your language, can you solve it in-place with ( O(1) ) extra space?
Solution
func reverseWords(s string) string {
c := reverseStr([]byte(s))
var result, word []byte
for i := 0; i < len(c); i++ {
if c[i] != ' ' {
word = append(word, c[i])
} else if len(word) > 0 {
result = append(result, reverseStr(word)...)
word = []byte{}
}
}
return string(result[:len(result)-1])
}
func reverseStr(word []byte) []byte {
l, r := 0, len(word)-1
for l < r {
word[l], word[r] = word[r], word[l]
l++
r--
}
return append(word, ' ')
}