412. Fizz Buzz

Given an integer n, return a string array answer (1-indexed) where:

• answer[i] == "FizzBuzz" if i is divisible by 3 and 5.
• answer[i] == "Fizz" if i is divisible by 3.
• answer[i] == "Buzz" if i is divisible by 5.
• answer[i] == i (as a string) if none of the above conditions are true.

Example 1:

Input: n = 3
Output: ["1","2","Fizz"]

Example 2:

Input: n = 5
Output: ["1","2","Fizz","4","Buzz"]

Example 3:

Input: n = 15
Output: ["1","2","Fizz","4","Buzz","Fizz","7","8","Fizz","Buzz","11","Fizz","13","14","FizzBuzz"]

Constraints:

• 1 <= n <= 10^4

Answer

func fizzBuzz(n int) []string {
    ans := []string{}
    
    for i := 1; i <= n; i++ {
        insert := ""
        if i % 3 == 0 {
            insert += "Fizz"
        }
        if i % 5 == 0 {
            insert += "Buzz"
        }
        if insert == "" {
            insert = strconv.Itoa(i)
        }

        ans = append(ans, insert)
    }
    return ans
}